extension before normal instruction:
$7180 > extract bits AA BB CCCCC DD

About the last one.
AA are the extended bits for operand a.
and BB are the extended bits for operand b.
and we get a new operand: C.

Now,
in AA or BB
Data become 4 banks (default D0..7 and 3 new E0..23)
and Address : lsb switch A0..7 and B0..7(if lsb=1)

So does the other bit of Address
when <ea> is present
switches <ea> to <vea>  (for $7100, line7 unused moveq)
like the lineF does?

I am thinking how a debugger would interpret it.

Thanks.

see:
Cpu Instructions, Color Mapping.
EXTERNAL LINK 
And in the 080 debugger "MonAm 3.09" you can see it by switching bank decoding on & off.
EXTERNAL LINK 
 
Documentation about 080 instructions:
EXTERNAL LINK