ammx instruction: $FE00 0000 > extract bits ABD AAAAAA BBBB DDDD oooooextension before normal instruction: $7180 > extract bits AA BB CCCCC DD About the last one. AA are the extended bits for operand a. and BB are the extended bits for operand b. and we get a new operand: C. Now, in AA or BB Data become 4 banks (default D0..7 and 3 new E0..23) and Address : lsb switch A0..7 and B0..7(if lsb=1) So does the other bit of Address when <ea> is present switches <ea> to <vea> (for $7100, line7 unused moveq) like the lineF does? I am thinking how a debugger would interpret it. Thanks.
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